POW Exhibition Reflection
The Problem of the Week that my group and I presented was the Bags of Gold King problem.
The problem was about a King who had 8 bags of gold and split them up between 8 different people in his kingdom. He thought that someone was stealing some of his gold so he brought all the gold together and wanted to weigh them in the least amount of ways as possible. You can way all 8 bags in 3 tries, but can you do it in 2?
We prepared for the exhibition by creating a poster and setting up a scale with bags that had gold covered chocolate in it.
Teaching the POW helped us improve our understanding of the problem by the way we explained it in our own words.
The problem was about a King who had 8 bags of gold and split them up between 8 different people in his kingdom. He thought that someone was stealing some of his gold so he brought all the gold together and wanted to weigh them in the least amount of ways as possible. You can way all 8 bags in 3 tries, but can you do it in 2?
We prepared for the exhibition by creating a poster and setting up a scale with bags that had gold covered chocolate in it.
Teaching the POW helped us improve our understanding of the problem by the way we explained it in our own words.
The Cookies Problem: Cover Letter and Graph
POW 5: Bales and Bales of Hay
Here is the basic run through of how it goes:
You have five bales of hay. For some reason, instead of being weighed individually, they were weighed in all possible combinations of two: bales 1 and 2, bales 1 and 3, bales 1 and 4, bales 1 and 5, bales 2 and 3, bales 2 and 4, and so on.
The weights of each of these combinations were written down and arranged in numerical order, without keeping track of which weight matched which pair of bales. The weights in kilograms were 80, 82, 83, 84, 85, 86, 87, 88, 90, and 91.
We were supposed to find out which two bales of hay went with weight. I found the answer first off by trying lots of different number. The closest I got for the weight of bale 1 was 39 kilograms. From there, I found bale 2 and used that weight to find bale 3. After that, I just tried a lot of fitting together which got me my answers.
Bale 1=39 kg
Bale 2=41 kg
Bale 3=43 kg
Bale 4=44 kg
Bale 5=47 kg
You have five bales of hay. For some reason, instead of being weighed individually, they were weighed in all possible combinations of two: bales 1 and 2, bales 1 and 3, bales 1 and 4, bales 1 and 5, bales 2 and 3, bales 2 and 4, and so on.
The weights of each of these combinations were written down and arranged in numerical order, without keeping track of which weight matched which pair of bales. The weights in kilograms were 80, 82, 83, 84, 85, 86, 87, 88, 90, and 91.
We were supposed to find out which two bales of hay went with weight. I found the answer first off by trying lots of different number. The closest I got for the weight of bale 1 was 39 kilograms. From there, I found bale 2 and used that weight to find bale 3. After that, I just tried a lot of fitting together which got me my answers.
Bale 1=39 kg
Bale 2=41 kg
Bale 3=43 kg
Bale 4=44 kg
Bale 5=47 kg